8x^2+50x-63=0

Solution for 8x^2+50x-63=0 equation:

8x^2+50x-63=0

a = 8; b = 50; c = -63;
Δ = b2-4ac
Δ = 502-4·8·(-63)
Δ = 4516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4516}=\sqrt{4*1129}=\sqrt{4}*\sqrt{1129}=2\sqrt{1129}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{1129}}{2*8}=\frac{-50-2\sqrt{1129}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{1129}}{2*8}=\frac{-50+2\sqrt{1129}}{16}
$